17³# One [ There may never be a # Two. ] 1 First seven primes: 2, 3, 5, 7, 11, 13, 17. 2 2 times 2 equals 4; 4 minus 1 equals 3, and plus 1/ 5. 3 3 is the sole prime number in the natural number summation sequence. 4 Excluding zero, the nnss consists of odd/even pairs. 5 First four: 1 3 | 6 10 | 15 21 | 28 36. 6 Each nnss pair is a set whose terms sum to an even square. 7 Excluding 1, multiples of 4 minus/plus 1 net odd numbers. 8 Let multiples of 4 be column 2 in a 3-column table. 9 For this table/ use the information found in the above two lines. 10 NB: 1 plus (8 times an nnss term) equals an odd square. 11 The final-digit set for column 1 is: 3 7 1 5 9. 12 The final-digit set for column 3 is: 5 9 3 7 1. 13 Between 3 times 3 and 5 times 5 in column 3 are three numbers. 14 An integer greater than 5 whose final digit is 5? Skip it. 15 Numerologically sums to 3, 6, 9? 3 eliminates. 16 14 rules 7 in 70-apart cycles: Make example. 17 Have know-ware to go, but am not sure how to share; yet searchings sustain. #

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## Monday, December 1, 2008

### tg00015

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## About Me

- brian (baj) salchert
- Rhodingeedaddee is my node blog. See
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## 1 comment:

I won’t pretend to understand this, except for the last line. Then again, how likely is it that I understand that when I don’t understand the preceding sixteen?

Had this been # Two, I could have a lot of fun imagining # One. As it is, # Two will be much more of a challenge.

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